Answer to Question #84057 in Mechanics | Relativity for hanna

Question

A 10 newton force acts on an object for 0.01 seconds. What force, acting on the object for 0.05 seconds, would produce the same impulse?

Answer 1

By the definition of the impulse, we get:

$$J = F∆t,$$

here,

$$J$$

is the impulse,

$$F$$

is the force acting on the object and

$$∆t$$

is the time interval at which the force acts on the object.

Then, from this formula we can find the impulse which produced by the

$$10 N$$

force acting on the object for 0.01 seconds:

$$J = F∆t = 10 N \cdot 0.01 s = 0.1 N \cdot s.$$

Then, the time at which the force acts on the object was change to 0.05 seconds. The force , acting on the object can be found from the same formula:

$$F = \frac{J}{∆t} = \frac{0.1 N \cdot s}{0.05 s} = 2 N.$$

Answer:

$$F = 2 N$$

.