Answer to Question #84047 in Mechanics | Relativity for christian

Question

A strong child pulls a block of wood with a force of100N at an angle of 50.0 degrees above the horizontal. Find the vertical and horizontal components of this pull.

Answer 1

a. Calculate the components of pull in X-direction by the relation as follows:

X-component of pull = F_X=Fcosθ

Here,F is the pull force and θ is the angle.

Substitute 100 N for F and 50° for θ.

F_x=(1000 N) )(cos⁡(50°)

F_x=642.78 N

b. Calculate the components of pull in Y-direction by the relation as follows:

Y-component of pull = F_Y=Fsinθ

Here ,F is the pull force and θ is the angle.

Substitute 100 N for F and 50° for θ.

F_Y=(1000 N) )(sin⁡(50°)

F_Y=766.04 N