Question #81862
A car of mass 1200kg falls a vertical distance of 24m starting from rest. What is the workdone by the the force of gravity on the car? ( g = 10$\frac{s}^2$)
1
Expert's answer
2018-10-11T10:33:09-0400

The work done is

W=E_2-E_1=mgh_2-mgh_1,

where h_2=0 – final height of the car. Therefore,

W=-mgh_1=-1200·10·24=-288000 J.

Work done by the force of gravity is negative.

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Place free inquiry
Calculate the price
Learn more about our help with Assignments: MechanicsRelativity

Comments

Assignment Expert
14.10.18, 20:36

Dear Bamidele temitayo, You're welcome. We are glad to be helpful. If you liked our service please press like-button beside answer field. Thank you!

Bamidele temitayo
12.10.18, 01:00

Thanks

Our fields of expertise
Submit Your Assignment. We Can Do It.
LATEST TUTORIALS
APPROVED BY CLIENTS
Finding a professional expert in "partial differential equations" in the advanced level is difficult. You can find this expert in "Assignmentexpert.com" with confidence. Exceptional experts! I appreciate your help. God bless you!
Canada #340153 on Dec 2023