Answer to Question #8098 in Mechanics | Relativity for Ashley
Question #8098
A rod of length 56.0 cm and mass 1.40 kg is suspended by two strings which are 42.0 cm long, one at each end of the rod.
The string on side B is cut. Find the magnitude of the initial acceleration of end B.
The string on side B is retied and now has only half the length of the string on side A.
Find the magnitude of the initial acceleration of the end B when the string is cut.
The string on side B is cut. Find the magnitude of the initial acceleration of end B.
The string on side B is retied and now has only half the length of the string on side A.
Find the magnitude of the initial acceleration of the end B when the string is cut.
Expert's answer
A rod of length 56.0 cm and mass 1.40 kg is suspended by two strings which are 42.0 cm long, one at each end of the rod.
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The string on side B is cut. Find the magnitude of the initial acceleration of end B.
&
The string on side B is retied and now has only half the length of the string on side A.
&
Find the magnitude of the initial acceleration of the end B when the string is cut.
When the string is cut rod rotates about other end. Let's take moment equation about that end:
mg*l/2 = Iα [I = ml^2/3]
mgl/2 = ml^2/3 * α
Angular acceleration:
& α = 3g/2l
Acceleration of end B:
a = lα = 3g/2 = 14.7 [g=9.8].
&
The string on side B is cut. Find the magnitude of the initial acceleration of end B.
&
The string on side B is retied and now has only half the length of the string on side A.
&
Find the magnitude of the initial acceleration of the end B when the string is cut.
When the string is cut rod rotates about other end. Let's take moment equation about that end:
mg*l/2 = Iα [I = ml^2/3]
mgl/2 = ml^2/3 * α
Angular acceleration:
& α = 3g/2l
Acceleration of end B:
a = lα = 3g/2 = 14.7 [g=9.8].
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