# Answer to Question #7939 in Mechanics | Relativity for Abigail

Question #7939

A rectangular fish tank measures 30 cm by 70 cm by 40 cm high. The tank is filled with water to a depth of 37 cm.

What is the pressure at the bottom due to the water?

What is the total force of the water on the bottom?

What is the pressure at the bottom due to the water?

What is the total force of the water on the bottom?

Expert's answer

The preassure of the water atthe bottom is equal to

p = rho g h,

where

rho = 1000 kg/m^3 is the density of water,

g = 9.8 m/c^2

h =

0.37 cm is the height of water.

Hence

p = 1000 * 9.8 * 0.37 =

3626 Pa

The forse is equal to

F = rho g V

where

V = 0.3

* 0.7 * 0.37 = 0.0777 m^3.

So,

F = 1000 * 9.8 * 0.0777 = 761.46 N

p = rho g h,

where

rho = 1000 kg/m^3 is the density of water,

g = 9.8 m/c^2

h =

0.37 cm is the height of water.

Hence

p = 1000 * 9.8 * 0.37 =

3626 Pa

The forse is equal to

F = rho g V

where

V = 0.3

* 0.7 * 0.37 = 0.0777 m^3.

So,

F = 1000 * 9.8 * 0.0777 = 761.46 N

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