A hollow brass tube (diameter = 3.40 cm) is sealed at one end and loaded with lead shot to give a total mass of 0.191 kg. When the tube is floated in pure water, what is the depth, z, of its bottom end?
Total Weight = Buoyant Force
mass * g = Buoyant Force
mass = 0.191 kg.
0.191 kg* 9.807= Specific Weight * Volume Submerged
---> Volume Submerged = Area * Depth
---> Specific Weight = p * g
--->p=1 g/cm3 = 1000kg / m3
--->Area = pi *(diameter / 2)^2 0.191 kg= p * g* Area* Depth