The displacement x variation of a particle with time t is given by expression x is equal to - 15t square + 20t + 30 find the position of the body at t is equal to zero second and t is equal to 6 seconds if this particle moving with uniform acceleration ?explain.
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Expert's answer
2018-04-24T08:58:08-0400
Find the position of the particle at t = 0 s: x(0)=-15×0+20×0+30=30 m
Find the position of the particle at t = 6 s: x(6)=-15×6^2+20×6+30=-390 m
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