Answer on Mechanics | Relativity Question for brawlf
θ(3) = (5 + 2*3²) = 23 rad;
Angular speed of the door:
θ'(t) = (5 + 2t²)' = 4t
Angular speed of the door at t = 3.0 s:
θ'(3) = 4*3 = 12 rad/s;
Angular acceleration of the door:
θ"(t) = (5 + 2t²)" = 4 rad/s² = const.
So, angular acceleration of the door at t = 3.0 s is 4 4 rad/s².
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