# Answer to Question #74451 in Mechanics | Relativity for chinemere john

Question #74451

a rectangular block of dimension 2.0*1.0*0.5* weighs 200N calculate the maximum pressure exerted by the block on a horizontal floor

Expert's answer

We can find the maximum pressure exerted by the block on a horizontal floor from the formula:

P=F/A,

here, P is the maximum pressure exerted by the block on a horizontal floor, F is the weight of the block, A is the area of the block.

Then, we get:

P=F/A=(200 N)/(0.01 m∙0.005 m)=4∙〖10〗^6 Pa.

P=F/A,

here, P is the maximum pressure exerted by the block on a horizontal floor, F is the weight of the block, A is the area of the block.

Then, we get:

P=F/A=(200 N)/(0.01 m∙0.005 m)=4∙〖10〗^6 Pa.

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