# Answer to Question #73473 in Mechanics | Relativity for VIt

Question #73473

The equation of motion of a damped harmonic oscillator is given by

d2x/dt2+2b dx/dt + w2x=0. m= 0.25 kg , b= 0.14/s and w = 18.4/s Calculate i) the time period; ii) number of oscillations in which its amplitude will become half of its initial value; and iii) number of oscillations in which its mechanical energy will reduce to half of its initial value.

d2x/dt2+2b dx/dt + w2x=0. m= 0.25 kg , b= 0.14/s and w = 18.4/s Calculate i) the time period; ii) number of oscillations in which its amplitude will become half of its initial value; and iii) number of oscillations in which its mechanical energy will reduce to half of its initial value.

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