Answer to Question #72636 in Mechanics | Relativity for Santhosh
y(x, t) = 3.0 sin (5.95t − 4.20x) cm
where x is the position along the wave propagation. Determine the amplitude, wave
number, wavelength, frequency and velocity of the wave. (2×5=10)
b) Two waves, travelling along the same direction, are given by
y1(x, t) = asin (w1t − k1x)
and y2 (x, t) = asin (w2t − k2x)
y(x,t)= A sin(ωt -kx)
Where A is the amplitude, ω is the angular frequency, k is a wave number.
Amplitude A=3.00 cm=0.03 m
Wave number k=4.20 m^(-1)
Wavelength λ=2π/k=2π/4.20=1.50 m
Velocity v=fλ=ω/k=5.95/4.20=1.42 m/s
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