# Answer to Question #72123 in Mechanics | Relativity for PREETISH KUMAR CHANDA

Question #72123

If a = v^1/2, then at t =0 and at v = 0 find initial velocity(u) ?

Expert's answer

Solution:

Acceleration: a=dv/dt=v^(1/2)

Then, by integrating: dv*v^(-1/2)=dt→2v^(1/2)=t (v(t=0)=0)

So, v(t)=t^2/4

Initial velocity: v(0)=0 (as its said in question)

Answer: 0

Acceleration: a=dv/dt=v^(1/2)

Then, by integrating: dv*v^(-1/2)=dt→2v^(1/2)=t (v(t=0)=0)

So, v(t)=t^2/4

Initial velocity: v(0)=0 (as its said in question)

Answer: 0

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