# Answer to Question #71811 in Mechanics | Relativity for PULKIT

Question #71811

The position of a particle moving in a straight line is given by x = 3 + 4t + 3t2, where x is in

metre and time is in second. Find the values of the following physical quantities for the particle

at t = 2s.

metre and time is in second. Find the values of the following physical quantities for the particle

at t = 2s.

Expert's answer

The particle motion law is given by

x = 3 + 4t + 3t^2

At the moment of time t=2 s

a) Position

x=3+4×2+3×2^2=23 m

b) Velocity

v(t)=x' (t)=4+6t

v(2)=4+6×2=16 m/s

c) Acceleration

a(t)=x'' (t)=6 m/s^2

x = 3 + 4t + 3t^2

At the moment of time t=2 s

a) Position

x=3+4×2+3×2^2=23 m

b) Velocity

v(t)=x' (t)=4+6t

v(2)=4+6×2=16 m/s

c) Acceleration

a(t)=x'' (t)=6 m/s^2

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## Comments

Assignment Expert08.01.18, 22:28Dear Asha Priyadharshini, you are right.

d = |x(0) - x(2)| = 20 m

Asha Priyadharshini08.01.18, 18:14It's wrong!

Displacement= 23-3= 20m

Assignment Expert18.12.17, 15:14Just a difference between starting position x(0) = 3 and final postion x(2) = 23:

d = |x(0) - x(2)| = 21 m.

pulkit narula17.12.17, 08:03displacement ?

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