Answer on Mechanics | Relativity Question for PULKIT
metre and time is in second. Find the values of the following physical quantities for the particle
at t = 2s.
x = 3 + 4t + 3t^2
At the moment of time t=2 s
a(t)=x'' (t)=6 m/s^2
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Dear Asha Priyadharshini, you are right.
d = |x(0) - x(2)| = 20 m
Displacement= 23-3= 20m
Just a difference between starting position x(0) = 3 and final postion x(2) = 23:
d = |x(0) - x(2)| = 21 m.