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Answer to Question #71811 in Mechanics | Relativity for PULKIT
Question #71811
The position of a particle moving in a straight line is given by x = 3 + 4t + 3t2, where x is in
metre and time is in second. Find the values of the following physical quantities for the particle
at t = 2s.
metre and time is in second. Find the values of the following physical quantities for the particle
at t = 2s.
Expert's answer
The particle motion law is given by
x = 3 + 4t + 3t^2
At the moment of time t=2 s
a) Position
x=3+4×2+3×2^2=23 m
b) Velocity
v(t)=x' (t)=4+6t
v(2)=4+6×2=16 m/s
c) Acceleration
a(t)=x'' (t)=6 m/s^2
x = 3 + 4t + 3t^2
At the moment of time t=2 s
a) Position
x=3+4×2+3×2^2=23 m
b) Velocity
v(t)=x' (t)=4+6t
v(2)=4+6×2=16 m/s
c) Acceleration
a(t)=x'' (t)=6 m/s^2
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#339914 on Dec 2023
#339914 on Dec 2023
Comments
Dear Asha Priyadharshini, you are right. d = |x(0) - x(2)| = 20 m
It's wrong! Displacement= 23-3= 20m
Just a difference between starting position x(0) = 3 and final postion x(2) = 23: d = |x(0) - x(2)| = 21 m.
displacement ?
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