Answer to Question #71391 in Mechanics | Relativity for Aires
A 5.5-kg rifle fires an 11 g bullet with a velocity of 1000 m/s. Question: if the shooter holds the rifle firmly against his shoulder,what will be the recoil velocity? Assume the mass of the shooter is 120 kg.
Initial momentum: P_i=mv=(0.011)(1000) kgm/s Initial momentum: P_f=(M+m^' )V. From the conservation of momentum: (M+m^' )V=mv The recoil velocity is V=m/((M+m^' ) ) v=(0.011)(1000)/(120+5.5)=0.09 m/s. Answer: 0.09 m/s.