Question #71391

A 5.5-kg rifle fires an 11 g bullet with a velocity of 1000 m/s. Question: if the shooter holds the rifle firmly against his shoulder,what will be the recoil velocity? Assume the mass of the shooter is 120 kg.

Expert's answer

Initial momentum:

P_i=mv=(0.011)(1000) kgm/s

Initial momentum:

P_f=(M+m^' )V.

From the conservation of momentum:

(M+m^' )V=mv

The recoil velocity is

V=m/((M+m^' ) ) v=(0.011)(1000)/(120+5.5)=0.09 m/s.

Answer: 0.09 m/s.

P_i=mv=(0.011)(1000) kgm/s

Initial momentum:

P_f=(M+m^' )V.

From the conservation of momentum:

(M+m^' )V=mv

The recoil velocity is

V=m/((M+m^' ) ) v=(0.011)(1000)/(120+5.5)=0.09 m/s.

Answer: 0.09 m/s.

## Comments

## Leave a comment