# Answer to Question #702 in Mechanics | Relativity for dennis

Question #702

A person walks 24 m East and then walks

40 m at an angle 28◦ North of East. What is the magnitude of the total displacement? Answer in units of m.

40 m at an angle 28◦ North of East. What is the magnitude of the total displacement? Answer in units of m.

Expert's answer

We have two displacements: r1, r2 ant total displacement r.

r1x=24m

r2x=40×cos(28°)=35.3179 m

rx=r1x+r2x=24+35.3179=59.3179 m

r1y=0

r2y=40×sin(28°)=18.7789 m

ry=r1y+r2y=0+18.7789=18.7789 m

Hence,

r=√rx²+ry²=√59.3179²+18.7789²=62.2185 m

r1x=24m

r2x=40×cos(28°)=35.3179 m

rx=r1x+r2x=24+35.3179=59.3179 m

r1y=0

r2y=40×sin(28°)=18.7789 m

ry=r1y+r2y=0+18.7789=18.7789 m

Hence,

r=√rx²+ry²=√59.3179²+18.7789²=62.2185 m

Need a fast expert's response?

Submit orderand get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

## Comments

## Leave a comment