a bullet from a 0.38 caliber handgun having a 6 inch barrel attains a muzzle speed of meters per second. assuming constant acceleration, how much time does it take the bullet to travel down the barrel?
We know that at²/2 = L, where L is a barrel length, a is an acceleration and t is a time while bullet is in a barrel. Also we know that at = V, here V is a muzle speed. So, a = V/t and at²/2 = L rewrites as (V/t)*t²/2 = L, or Vt/2 = L ==> t = 2L/V = 2*6/V = 12/V.