# Answer to Question #6872 in Mechanics | Relativity for Sam

Question #6872

A mass 10kg is dropped from a height of 50cm.Find its

a)Potential Energy just before dropping.

b)Kinetic Energy just on touching the ground.

c)Velocity with which it hits the ground (given g=10ms-2)

a)Potential Energy just before dropping.

b)Kinetic Energy just on touching the ground.

c)Velocity with which it hits the ground (given g=10ms-2)

Expert's answer

a) Potential energy

Ep=mgh=10kg*10m/s

b) Due to conservation of energy law

Ek=Ep=50 J

c) We know that Ek=mv

v=sqrt(2*Ek/m)=sqrt(2*50/10)=sqrt(10)=3,16 m/s

Ep=mgh=10kg*10m/s

^{2}*0.5m=50 Jb) Due to conservation of energy law

Ek=Ep=50 J

c) We know that Ek=mv

^{2}/2 hence we can find velocityv=sqrt(2*Ek/m)=sqrt(2*50/10)=sqrt(10)=3,16 m/s

## Comments

## Leave a comment