Answer to Question #6702 in Mechanics | Relativity for yah
S = 4πr² = 4π1² = 4π.
We denote the inside pressure force by Fi and outside pressure force by Fo. When the radius is r=1 the values of these forces are:
Fi = S*5200 = 4π5200 = 20800π,
Fo = S*3200 = 4π3200 = 12800π.
We see that Fi > Fo.
We know that inside pressure force is constant under the volume changes. Let's denote the new radius of the vessel by R.
Fi = Fo
20800π = 3200*4πR² ==> R = sqrt(20800/4/3200) = sqrt(1.625) = 1.2747
So, the vessel must expand a bit, then the outside pressure will grow up.
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