Question #61580

A large man sits on a four-legged chair with his feet off the floor. The combined mass of the man and chair is 95.0 kg. If the chair legs are circular and have a radius of 0.500 cm at the bottom, what pressure does eachleg exert on the floor
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Expert's answer

2016-08-30T11:15:03-0400

Answer on Question 61580, Physics, Other

Question:

A large man sits on a four-legged chair with his feet off the floor. The combined mass of the man and chair is 95.0 kg. If the chair legs are circular and have a radius of 0.5 cm at the bottom, what pressure does each leg exert on the floor?

Solution:

By the definition of the pressure we have:


P=FA,P = \frac {F}{A},


here, PP is the pressure that each leg exert on the floor, FF is the force acting on the floor, AA is the total area of the four legs.

The force acting on the floor is the weight of the man and chair:


F=W=mg,F = W = m g,


here, mm is the combined mass of the man and chair, gg is the acceleration due to gravity.

We can find the total area of the four legs from the formula:


A=Nπr2,A = N \pi r ^ {2},


here, NN is the number of the chair legs, rr is the radius of the chair leg.

Finally, substituting FF and AA into the formula, we get:


P=FA=mgNπr2=95kg9.8ms24π(0.005m)2=2.96106Pa.P = \frac {F}{A} = \frac {m g}{N \pi r ^ {2}} = \frac {9 5 k g \cdot 9 . 8 \frac {m}{s ^ {2}}}{4 \cdot \pi \cdot (0 . 0 0 5 m) ^ {2}} = 2. 9 6 \cdot 1 0 ^ {6} P a.


Answer:

The pressure that each leg exert on the floor is P=2.96106PaP = 2.96 \cdot 10^{6} Pa.

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