Answer to Question #6048 in Mechanics | Relativity for Erica Evoli

Question #6048
The International Space Station is orbiting at an altitude of about 370 km above the earth's surface. The mass of the earth is 5.976 × 10 24 kg and the radius of the earth is 6.378 × 10 6 m. (a) Assuming a circular orbit, what is the period of the International Space Station's orbit? (b) Assuming a circular orbit, what is the speed of the International Space Station in its orbit
1
Expert's answer
2012-01-20T07:22:15-0500
(a)& Assuming a circular orbit, what is the period of the International Space Station's
orbit?

The gravitation force is equal to the centripetal force:

GMm/r² = mV²/r, or GM/r = V².

T = 2pi*r / V
V² = [ 2pi r / T ]²
GM/r = [ 2pi r / T ]²
6.67*10^(-11) * 5.98*10^24 / [ (6.378*10^6 + 370*10³ ) ]³ = [ 2pi / T]²
T = 5514s

(b)& Assuming a circular orbit, what is the speed of the International Space Station in its
orbit

V = sqrt [ 6.67*10^(-11) * 5.98*10^24 / [ [ (6.378*10^6 + 370*10³ )]
V = 7690 m/s.

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be first!

Leave a comment

Ask Your question

LATEST TUTORIALS
New on Blog
APPROVED BY CLIENTS
paypal