a box slides down at constant velocity along an inclined plane which makes angle x with the horizon. if the box is now given an initial velocity v in the upward direction along the plane, what would be the displacement of the box
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If box goes with constant velocity means coff. Of friction(u)=
tanx...condition just to start slipping..... When pushed up the
incline 2 forces act mgsinx and umgcosx in downward direction So
mgsinx+ umgcosx= ma... --> mgsinx+(tanx)mgcosx=ma --> mgsinx+ mgsinx=
ma -->2gsinx=a a is deaccelarting the block.... Apply v^2 - u^2= 2as
Here v= 0( final velocity), u=v( given initial velocity) Therofore, s=
v^ 2 /4gsinx
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Dear Abhishek thank you
If box goes with constant velocity means coff. Of friction(u)= tanx...condition just to start slipping..... When pushed up the incline 2 forces act mgsinx and umgcosx in downward direction So mgsinx+ umgcosx= ma... --> mgsinx+(tanx)mgcosx=ma --> mgsinx+ mgsinx= ma -->2gsinx=a a is deaccelarting the block.... Apply v^2 - u^2= 2as Here v= 0( final velocity), u=v( given initial velocity) Therofore, s= v^ 2 /4gsinx
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