Question #5571

A rock with a mass of 6.0 kg is being whirled in a horizontal circle on the end of a rope 1.6m long. If the speed of the rock is 2.7m/s , what is the magnitude of the centripetal acceleration?

Expert's answer

The liniar velocity of a point at the tub is 2.7 m/s, so centripetal acceleration is

Ac = V²/R = 2.7²/1.6 = 4.55625 m/s².

The magnitude of the centripetal acceleration is called the centrifugal force and it is

F = M*Ac = 6.0*4.55625 = 27.3375 N.

Ac = V²/R = 2.7²/1.6 = 4.55625 m/s².

The magnitude of the centripetal acceleration is called the centrifugal force and it is

F = M*Ac = 6.0*4.55625 = 27.3375 N.

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