# Answer to Question #5390 in Mechanics | Relativity for Rebecca

Question #5390

4 students are pulling on the same object in 4 different directions.One student pulls with a force of 5.5N to the west, the second student oulls with a force 8.75N to the north, the third student pulls with a force of 10.15 to the south and the fourth student pulls with a force of 4.0 to the east. IF the objext has a mass of 0.kg find:

A) Fnet x

B)Fnext y

C)Fnet

D) Acceleration

A) Fnet x

B)Fnext y

C)Fnet

D) Acceleration

Expert's answer

8.75N North

& & & & & |

& & |

& & & & & |

& & & & & & |

west& ___|____ & 4.0N

5.5N & | & & & & East

& & & & & |

& & & & & |

& & & & & |

& & |

& 10.15N South

A) Fnet x

As we see from the flowchart,

Fnetx = 4.0N - 5.5N = -1.5N

B)Fnext y

Fnexty = 8.75N - 10.15N = -1.40N

C)Fnet

Fnet = sqrt(Fnetx² + Fnety²) = sqrt(1.5²+1.40²) = sqrt(4.21) ≈ 2,0518N

D) Acceleration

Let's use the second Newton's law:

Fnet = ma ==> a = Fnet/m = 2,0518N/0.

As the object has zero mass by definition, the acceleration is unlimited.

& & & & & |

& & |

& & & & & |

& & & & & & |

west& ___|____ & 4.0N

5.5N & | & & & & East

& & & & & |

& & & & & |

& & & & & |

& & |

& 10.15N South

A) Fnet x

As we see from the flowchart,

Fnetx = 4.0N - 5.5N = -1.5N

B)Fnext y

Fnexty = 8.75N - 10.15N = -1.40N

C)Fnet

Fnet = sqrt(Fnetx² + Fnety²) = sqrt(1.5²+1.40²) = sqrt(4.21) ≈ 2,0518N

D) Acceleration

Let's use the second Newton's law:

Fnet = ma ==> a = Fnet/m = 2,0518N/0.

As the object has zero mass by definition, the acceleration is unlimited.

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