98 943
Assignments Done
98.8%
Successfully Done
In May 2021

# Answer to Question #5360 in Mechanics | Relativity for Mario

Question #5360
A 1927 kg car has a speed of 10.3 m/s when it hits a tree. The tree doesn&rsquo;t move and the car comes to rest. Find the change in kinetic energy of the car.

Find the amount of work done by the car as its front is pushed in.

Find the magnitude of the force that pushed the front of the car in by 48 cm .
1
2011-12-01T08:47:52-0500
Let's make following denotations:
M = 1927 kg;
V0 = 10.3 m/s;
L = 0.48 m.

The energy of a car was
E0 = (M*V0&sup2;)/2 = (1927*10.3&sup2;)/2 = 102217.715 J.
and became
E1 = 0.
So, the change in kinetic energy is E0-E1 = 102217.715 - 0 = 102217.715 J.

Find the amount of work done by the car as its front is pushed in. Answer in units of J.
The amount of work is equal to the kinetic energy change:
A = E0-E1 = 102217.715 J.
&
Find the magnitude of the force that pushed the front of the car in by 48 cm. Answer in units of N

Let's find the acceleration of the car while it stopped:
a = (V0 - V1)/T.
Here T = 2*L/V0 is the time car to stop after hit and V1 = 0. So,
a = (V0 - V1)*V0/(2*L) = 10.3&sup2;/(0.48*2) =& 110.51 m/s&sup2;.
Now let's use the second Newton's law:
F = M*a = 1927*110.51 = 212953.57 N.

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!