Answer to Question #5299 in Mechanics | Relativity for shameza
Let's make the following denotations:
M1 = 2kg - first block mass
M2 = 4kg - second& block mass
E - extension of a spring
Let's find the extension of a spring at the state of equilibrium:
g*M2 = k*E ==> E = g*M2/k = 9.8*4/40 = 0.98 m.
So, the maximum extension of the spring is 98 cm.
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