# Answer to Question #52483 in Mechanics | Relativity for Helen

Question #52483

A meter stick moving at 0.900c relative to the Earth's surface approaches an observer at rest with respect to the Earth's surface. What is the meter sticks length as measured by the observer? Qualitatively, how would the answer to that change if the observer started running toward the meter stick?

Expert's answer

Solution:

L' = L*sqrt( 1 - V^2/C^2) = L*sqrt(1 - 0.95*0.95) = L* sqrt(1 - 0,9025) = L* sqrt(0,0975) = L*0,312

The linear length L' of the stick moving at a speed = 0.9 C for a stationary observer will be

0.312 * L, where L is the linear size of the ship stationary relative to observer

If L = 1 m then L' = 0,312 m

Qualitatively, how would the answer to that change if the observer started running toward the meter stick?

Answer:

I think if the meter stick is stationary observer moves but the situation has not changed

meter stick will appear to the observer is shorter

and its length will be the same 0.312 m

L' = L*sqrt( 1 - V^2/C^2) = L*sqrt(1 - 0.95*0.95) = L* sqrt(1 - 0,9025) = L* sqrt(0,0975) = L*0,312

The linear length L' of the stick moving at a speed = 0.9 C for a stationary observer will be

0.312 * L, where L is the linear size of the ship stationary relative to observer

If L = 1 m then L' = 0,312 m

Qualitatively, how would the answer to that change if the observer started running toward the meter stick?

Answer:

I think if the meter stick is stationary observer moves but the situation has not changed

meter stick will appear to the observer is shorter

and its length will be the same 0.312 m

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