Answer on Mechanics | Relativity Question for Helen
L' = L*sqrt( 1 - V^2/C^2) = L*sqrt(1 - 0.95*0.95) = L* sqrt(1 - 0,9025) = L* sqrt(0,0975) = L*0,312
The linear length L' of the stick moving at a speed = 0.9 C for a stationary observer will be
0.312 * L, where L is the linear size of the ship stationary relative to observer
If L = 1 m then L' = 0,312 m
Qualitatively, how would the answer to that change if the observer started running toward the meter stick?
I think if the meter stick is stationary observer moves but the situation has not changed
meter stick will appear to the observer is shorter
and its length will be the same 0.312 m
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