# Answer to Question #5180 in Mechanics | Relativity for Nida

Question #5180

A turntable is designed to acquire an angular

velocity of 33.5 rev/s in 0.5 s, starting from

rest.

Find the average angular acceleration of th

turntable during the 0.5 s period.

Answer in units of rad/s

velocity of 33.5 rev/s in 0.5 s, starting from

rest.

Find the average angular acceleration of th

turntable during the 0.5 s period.

Answer in units of rad/s

Expert's answer

Let a be the angular acceleration of a turntable. Then

W = aT,

where W is the final angular velocity and T is the acceleration time. So,

a = W/T = (33.5 rev/s) / (0.5 s) = 67 rev/s² = 67·2π rad/s² = 134π rad/s².

W = aT,

where W is the final angular velocity and T is the acceleration time. So,

a = W/T = (33.5 rev/s) / (0.5 s) = 67 rev/s² = 67·2π rad/s² = 134π rad/s².

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