Answer to Question #51095 in Mechanics | Relativity for hardeep chopra

Question

When meteors enter the atmosphere, they are typically traveling at around 15km/s. At such

speeds, heat does not have time to be conducted away and even the air has no time to be pushed out of the way. This results in adiabatic compression of the air ahead of the meteor. The density of the atmosphere in kg/m3 is given by

rho=1.22e^(h/8100)

where h is the altitude in meters.

a) For a spherical meteor of radius 5m entering the atmosphere on a vertical trajectory, As a result of compressing all the air in its way into a cylinder of radius 5.5m and height 0.3m, there

will be a very high pressure and temperature in front of the meteor. Calculate the density of air in this compression zone when the meteor has reached an altitude of 4050m by finding the kg of air compressed and the volume of the compression zone. Hint: dm = ?Adh

b) Calculate the original volume of the gas before it was compressed. You may use h=40,000m as the top of the atmosphere.

c) Calculate the average pressure using where h = altitude in meters. Calculate the average pressure as Pavg = [?Pdh]/?h

d) Now find the adiabatic constant using the average pressure from (b) and the original volume from (a). Take Cp/Cv = 1.35 for air.

e) Show that the ideal gas law can be written as where M for air is about

25.6x10-3 kg/mol. f) Use the results from (e) (d) and (a) to get the pressure of the compressed gas at h=4050

meters. Take Cp/Cv = 1.35 for air. Compare the pressure to the ultimate strengths for rock(107Pa) and iron(108Pa) to see if the meteor explodes. g) Using the results from (e) and (f), calculate the temperature in the compression zone at h=4050 meters. h) At the temperature calculated in (g), determine the wavelength of the maximum intensity and

the total power emitted by the hot gas (using a surface area of 2? 5.52 for the flattened spheroid of gas).

Answer 1

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