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# Answer to Question #50084 in Mechanics | Relativity for prack

Question #50084
This question refers to: Laws of motion
A mass of 2 kg travelling at 2 m/s is struck by a mass of 4 kg travelling at 3 m/s. If the coefficient of restitution for the two materials is 0.4, calculate their final velocities.
Give the final velocity value in m/s of the 4kg mass here:
Given:
m1=2
v1b=2 &nbsp;(velosity before collision)
m2=4 &nbsp;&nbsp;
v2b=3 &nbsp;(velosity before collision)&nbsp;
cr=0.4 (coeffitient of restitution)
We want to find v1a (velosity after collision)-?
Solution:
According ofComversation of the &nbsp;impulse
m1*v1b - m2*v2b = - m1*v1a + m2*v2a
and
definition of coeffitient of restitution
cr= (v1b-v1a)/(v2a-v2b)
we have
v1a= [(m1*v1b-m2*v2b)-(m2*v2+m2*v1b/cr)]/[m1-m2/cr]=4 m/s
v2a=v2b+(v1b-v2a)/cr=-2 m/s

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