Answer to Question #49875 in Mechanics | Relativity for tinu
the solution is like this
let the upper direction is positive
then we can write
-h=ut-1/2gt^2 and t=6s .
my question is why h =10 is used here. i have thrown the ball from 58.8m upward. then it should have a height to the up and when it will fall downward then after crossing the roof it should have a height of 58.8m. so why in these case that upper height is not used .
my same question is also for projectile thrown from a height. there, also the upper height is not counted why?? why only the given height is used to solve the problems.
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