Answer to Question #49185 in Mechanics | Relativity for Trevor

Mechanics | Relativity

Question #49185

In the deepest part of Lake Superior, the water depth is 406 m. What is the pressure at this depth?

Expert's answer

The pressure at this depth is p=density of the water * depth * acceleration of gravity = 1000 * 406 * 9,81 = 3982860 Pa = 39.3 Atm

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