# Answer on Mechanics | Relativity Question for Rachel

Question #4904

A cannon mounted on a pirate ship fires a cannonball at 125 m/s horizontally, at a height of 17.5 m above the ocean surface. Ignore air resistance. (a) How much time elapses until it splashes into the water? (b) How far from the ship does it land?

(a)

(a)

Expert's answer

A cannon mounted on a pirate ship fires a cannonball at Vh=125 m/s horizontally, at a height of 17.5 m above the ocean surface. Ignore air resistance.

(a) How much time elapses until it splashes into the water?

Initial vertical velocity Vv of a cannonball is equal to zero cause cannon fires horizontally. The gravity is acting on a cannonball, and Vv(t) = gt. So, (Vv^2)/2 = (gt^2)/2 = 17.5. Here we get T = sqrt(2*17.5/g) = sqrt(2*17.5/9.8) = 1,9 s.

(b) How far from the ship does it land?

While falling down the cannonball will cover the distance D = Vh*T = 125*1.9 = 237.5 m.

(a) How much time elapses until it splashes into the water?

Initial vertical velocity Vv of a cannonball is equal to zero cause cannon fires horizontally. The gravity is acting on a cannonball, and Vv(t) = gt. So, (Vv^2)/2 = (gt^2)/2 = 17.5. Here we get T = sqrt(2*17.5/g) = sqrt(2*17.5/9.8) = 1,9 s.

(b) How far from the ship does it land?

While falling down the cannonball will cover the distance D = Vh*T = 125*1.9 = 237.5 m.

Need a fast expert's response?

Submit orderand get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

## Comments

## Leave a comment