Answer to Question #4904 in Mechanics | Relativity for Rachel
(a) How much time elapses until it splashes into the water?
Initial vertical velocity Vv of a cannonball is equal to zero cause cannon fires horizontally. The gravity is acting on a cannonball, and Vv(t) = gt. So, (Vv^2)/2 = (gt^2)/2 = 17.5. Here we get T = sqrt(2*17.5/g) = sqrt(2*17.5/9.8) = 1,9 s.
(b) How far from the ship does it land?
While falling down the cannonball will cover the distance D = Vh*T = 125*1.9 = 237.5 m.
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