# Answer to Question #4904 in Mechanics | Relativity for Rachel

Question #4904

A cannon mounted on a pirate ship fires a cannonball at 125 m/s horizontally, at a height of 17.5 m above the ocean surface. Ignore air resistance. (a) How much time elapses until it splashes into the water? (b) How far from the ship does it land?

(a)

(a)

Expert's answer

A cannon mounted on a pirate ship fires a cannonball at Vh=125 m/s horizontally, at a height of 17.5 m above the ocean surface. Ignore air resistance.

(a) How much time elapses until it splashes into the water?

Initial vertical velocity Vv of a cannonball is equal to zero cause cannon fires horizontally. The gravity is acting on a cannonball, and Vv(t) = gt. So, (Vv^2)/2 = (gt^2)/2 = 17.5. Here we get T = sqrt(2*17.5/g) = sqrt(2*17.5/9.8) = 1,9 s.

(b) How far from the ship does it land?

While falling down the cannonball will cover the distance D = Vh*T = 125*1.9 = 237.5 m.

(a) How much time elapses until it splashes into the water?

Initial vertical velocity Vv of a cannonball is equal to zero cause cannon fires horizontally. The gravity is acting on a cannonball, and Vv(t) = gt. So, (Vv^2)/2 = (gt^2)/2 = 17.5. Here we get T = sqrt(2*17.5/g) = sqrt(2*17.5/9.8) = 1,9 s.

(b) How far from the ship does it land?

While falling down the cannonball will cover the distance D = Vh*T = 125*1.9 = 237.5 m.

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