57 380
Assignments Done
99%
Successfully Done
In February 2018
Your physics homework can be a real challenge, and the due date can be really close — feel free to use our assistance and get the desired result.
Be sure that math assignments completed by our experts will be error-free and done according to your instructions specified in the submitted order form.
Our experts will gladly share their knowledge and help you with programming homework. Keep up with the world’s newest programming trends.

Answer on Mechanics | Relativity Question for jojo

Question #4683
Tom and Jill are both robots that are going to have a race. Both start from rest. Tom has a constant acceleration for the entire run, while Jill does the following; first she accelerated for a time of 2.00 minutes(convert to seconds) at a rate of 2.20cm/s/s ( must convert to meters), then runs a distance of 18.9 kilometers reaching a final velocity of 23.7 m/s, thetn decelerates at a rate of 2.3m/s/s, finishing the race with a velocity of 6.00m/s.

If Tom ties with Jill, what would have to be his final velocity?
Expert's answer
a- acceleration of Tom

a1=0.022m/sec^2-accel. Of Jill

1)velocity after two min of Jill =120*0.022=2.64m/sec

S=at^2/2=158m

2)distance of 18.9 kilometers reaching a final velocity of 23.7 m/s

s=& so a=2*18900/

at=23.7 m/s-2.64m/sec=21.06

s=& =t21.06/2

t=18900/10.53=1795sec

a=1.17m/sec^2 {at the distance of 18.9 kilometers reaching a final velocity of 23.7 m/s}

S=18900m

3) , thetn decelerates at a rate of 2.3m/s/s, finishing the race with a velocity of 6.00m/s

t*2.3=23.7-6

t=8sec.

S=vt-at^2/2=23.7*8-2.3*64/2=116m

total time- 120+1795+8sec=1923

total path = 158+18900+116=19174

4)Tom:

S=at^2/2

19174=a*1848964.5

a=0.01m/sec^2

final velocity=at=1923*0.01=19.23m/sec^2

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be first!

Leave a comment

Ask Your question