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Answer to Question #4643 in Mechanics | Relativity for jessica sean

Question #4643
A force of 8.75N is applied to a mass of 3.5kg placed on a horizontal surface. If the coefficient of friction is placed between the mass and the surface is 0.2, what is the mass of acceleration?
Expert's answer
According to the Second Newton's Law:
ma = F - Friction.
Friction = 0.2 *
mg.
So,&
ma = F - 0.2mg. We get
a = F/m - 0.2g = 8.75/3.5 - 0.2*9.8 =
0.54 m/s^2

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