Answer to Question #4303 in Mechanics | Relativity for Mike
(a) If its initial velocity is 5.9 m/s, what is its displacement during the time interval?
(b) What is the distance it travels during this interval?
(c) If its initial velocity is
m/s, what is its displacement during the time interval?
(d) What is the total distance it travels during the interval in part (c)?
Vf=11.8 final velosity of an object
V0=5.9 initial velosity
a) if an object moves with constant acceleration we can find its velosity at any time moment using formula
from that formula we can find t:
t=(Vf-V0)/a=(11.8-5.9)/3.4 =1.74 s - total time
where S0- initial position, S0=0
So displacement S=5.9*1.74+3.4*1.74^2/2=10.2+5.15=15.25 m
distance is same thing as displacement here, because S>0 . In general distance is scalar quantity and displacement has direction(it's vector quantity)
b) distance& 15.25 m as explained above
c ) Now V0=-5.9
distance is same thing as displacement here, because S>0 . So distance D=15.1 m
d)distance D=15.1 m
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