98 972
Assignments Done
98.9%
Successfully Done
In May 2021

# Answer to Question #4178 in Mechanics | Relativity for moha

Question #4178
A half inch garden hose can discharge five hundred gallons of water per hour under normal water pressure conditions.
What is the velocity of water leaving the garden hose under these conditions, in ft/min?
1
2011-09-08T11:57:47-0400
We know that the garden hose can discharge five hundred gallons of water per hour.So, V / t = 5 gallons / h, where V is the volume.
Suppose, the hose has a cylindrical form. Then
V = S*L, where S is the cross-sectional area, S=pi*R﻿*R.
We know the diameter d = 0.5 inch, then R = 0.25 inch.
We need to calculate L / t but before we do this, we must convert all the
measurements to the standard form:

R = 0.25 inch = 0.00635 m, V / t = 5 gallons/h = 0.01893 m^3 / h.

So, L / t = V /(S t) = 0.01893 / (pi*0.00635^2) = 149.4 m / h = 8.2 ft/min.

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!