Answer to Question #3865 in Mechanics | Relativity for mia
Let S be the distance between the target and the plane’'s projection onto the ground.
As the pilot drops the object, it covers the height H during the time t:
So t = sqrt(2*H/g).
During the time t, the object covers the distance S along the x-axis:
S = V*t.
S = V*sqrt(2*H/g).
The pilot sees the target at the angle A with the horizont:
A = arctan(H/S) = aarctan (H/(V*sqrt(2*H/g))).
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