Answer to Question #3848 in Mechanics | Relativity for mia
horizontally, strikes it head on. The dart and the target together swing up 12 cm above the
initial level. What was the initial velocity of the dart?
V - initial velocity of the dart.
Consider the target and the dart didn't have the initial potential energy,
let's use the law of conservation of energy:
E1 = E2,
E1 - initial energy of the system,
E2 - energy of the system after the collision.
E1 = Ek - kinetic energy,
E2 = Ep - potential energy
m1*V2 = (m1 + m2)*g*h
V = sqrt((m1+m2)*g*h/m1)
V = sqrt((0.025+0.73)*9.8*0.12/0.025) = 5.96 m/s.
So, the initial velocity of the dart is 5.96 m/s.
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