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Answer to Question #3846 in Mechanics | Relativity for mia

Question #3846
A thread holds two carts together on a frictionless surface as in the figure below. A
compressed spring acts on the carts. After the thread is burned, the 1.5 kg cart moves with
a velocity of 27 cm/s to the left. What is the velocity of the 4.5 kg cart?
Expert's answer
Let m1 be the mass of the first cart (m1 = 1.5 kg), m2 - the mass of the second cart (m2 = 4.5 kg).
V1 - velocity of the first cart, V2 - velocity of the second cart.
According to the law of conservation of linear momentum:


0 = m1V1 - m2V2
V2 = V1*m1/m2
V2 = 27*1.5/4.5 = 9 cm/s


So, the velocity of the 4.5 kg cart is 9 cm/s.

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