# Answer to Question #3846 in Mechanics | Relativity for mia

Question #3846

A thread holds two carts together on a frictionless surface as in the figure below. A

compressed spring acts on the carts. After the thread is burned, the 1.5 kg cart moves with

a velocity of 27 cm/s to the left. What is the velocity of the 4.5 kg cart?

compressed spring acts on the carts. After the thread is burned, the 1.5 kg cart moves with

a velocity of 27 cm/s to the left. What is the velocity of the 4.5 kg cart?

Expert's answer

Let m

V

According to the law of conservation of linear momentum:

0 = m

V

V

So, the velocity of the 4.5 kg cart is 9 cm/s.

_{1}be the mass of the first cart (m_{1}= 1.5 kg), m_{2}- the mass of the second cart (m_{2}= 4.5 kg).V

_{1 }- velocity of the first cart, V_{2}- velocity of the second cart.According to the law of conservation of linear momentum:

0 = m

_{1}V_{1 }- m_{2}V_{2}V

_{2}= V_{1}*m_{1}/m_{2}V

_{2}= 27*1.5/4.5 = 9 cm/sSo, the velocity of the 4.5 kg cart is 9 cm/s.

## Comments

## Leave a comment