Answer on Mechanics | Relativity Question for mia
compressed spring acts on the carts. After the thread is burned, the 1.5 kg cart moves with
a velocity of 27 cm/s to the left. What is the velocity of the 4.5 kg cart?
V1 - velocity of the first cart, V2 - velocity of the second cart.
According to the law of conservation of linear momentum:
0 = m1V1 - m2V2
V2 = V1*m1/m2
V2 = 27*1.5/4.5 = 9 cm/s
So, the velocity of the 4.5 kg cart is 9 cm/s.
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