Answer to Question #3844 in Mechanics | Relativity for mia
opposite direction at a velocity of –12.0 m/s. <br>The 0.50 kg ball moves away at –14 m/s after
the collision. Find the velocity of the second ball.
U1, V1 - speeds of the first ball before and after the collision, U2, V2 - speeds of the second ball before and after the collision.
According to the law of conservation of linear momentum (let the initial direction of the first ball be positive):
m1U1 - m2U2=-m1V1 + m2V2
V2 = (U1 + V1)*m1/m2 - U2
V2 = (6 + 14)*0.5/1 - 12 = -2 m/s.
So, the second ball continued moving at the same direction at 2 m/s.
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