# Answer to Question #3822 in Mechanics | Relativity for mia

Question #3822

A stream of doubly-ionized particles (missing two electrons and thus carrying a net charge

of two elementary charges) moves at a velocity of 3.0 × 104 m/s perpendicular to a

magnetic field of 9.0 × 10–2 T. What is the magnitude of the force acting on each ion?

of two elementary charges) moves at a velocity of 3.0 × 104 m/s perpendicular to a

magnetic field of 9.0 × 10–2 T. What is the magnitude of the force acting on each ion?

Expert's answer

We know that the Lorentz force is

F = q [v × B], where q is the charge of the particle 2e = 2 * 1.6*10

F = 3.2*10

F = q [v × B], where q is the charge of the particle 2e = 2 * 1.6*10

^{-19}C = 3.2*10^{-19}C , [v × B] - is the vector multiplication of the velocity and the magnetic field, v is perpendicular to B.F = 3.2*10

^{-19}* 3.0*10^{4}* 9.0 *10^{–2}= 8.64 x 10^{–16}Need a fast expert's response?

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