Answer to Question #3803 in Mechanics | Relativity for Vikas
A force is applied on a body mass 50 kg for 8 sec. After that force is removed, but the body continuous in motion for 5 sec and covers 80m displacement. Find the force applied.
Let's denote the force as F. If 80 m is the distance that the body covers after 8 sec, we can find the the constant velocity : V = S/t2 = 80/5 = 16 m/s. V = at1 = F/m *t = F/ 50 * 8 = 16 m/s F = 100 N
If 80 m is the total distance covered by the body: The acceleration whould be a = F/m = F/50, the velocity after 8 sec is V = at = F/50 * 8 = 4F/25 m/s. The distance after 8 sec is D = at2/2 = F/50 * 64 / 2 = 16F/25 m. Then the body is moving for 5 sec with constant velocity: S = Vt = 4F/25 *5 = 4F/5 m. The total distance is 80 m: 16F/25 + 4F/5 = 80 (16 + 20) F/ 25 = 80 F = 80*25/36 = 55 5/9 = 55.56 N
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