# Answer to Question #37253 in Mechanics | Relativity for alzahra

Question #37253

What power is needed to lift a 49-kg person a vertical distance of 5.0 m in 20.0 s?

Expert's answer

Solution:

Power=Work/time

Work=Force*Distance (in our case)

Force=m*g (lifting force is equal to weight of the body)

now numbers

m=49kg

Distance=5m

time=20s

g=10H/kg

Force=m*g=49kg*10N/kg=490N

Work=Force*distance=490N*5m=2450Nm

Power=Work/time=2450Nm/20s=122.5Nm/s=122.5Watt

ANSWER:

Power=122.5Watt

Power=Work/time

Work=Force*Distance (in our case)

Force=m*g (lifting force is equal to weight of the body)

now numbers

m=49kg

Distance=5m

time=20s

g=10H/kg

Force=m*g=49kg*10N/kg=490N

Work=Force*distance=490N*5m=2450Nm

Power=Work/time=2450Nm/20s=122.5Nm/s=122.5Watt

ANSWER:

Power=122.5Watt

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