Answer to Question #36957 in Mechanics | Relativity for ammy

Question

An open water tank has an orifice 10cm below the surface of water .if there is no loss of energy ,then what is the speed of efflux ???????????????????????????????? (take g=10 m/s square )

Answer 1

v^2/2 + gz + p/rho = const.

we have the same pressure, as the tank is opened, hence

v^2/2+gh=const.

Hence

v^2/2 = gz

v = sqrt(2gz) = sqrt(2*10*0.1) = sqrt(2) = 1.41 m/s