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# Answer to Question #3618 in Mechanics | Relativity for Chalani Jayawardena

Question #3618
A = 8kg , 10 ms-1 and moves to East
&lt;br&gt;B = 5kg , 20ms-1 and moves to North
&lt;br&gt;-Before Hitting-
&lt;br&gt;
A+B = 13kg&lt;br&gt;& -After Hitting-
&lt;br&gt;
if the hitting is fully unelastic, find the velocity of A and B after hitting.What is the direction that A+B moves after hitting.
1
2011-07-14T06:34:35-0400
We should add the& vectors& of impulse A and B
Pa = MaVa = 8*10 = 80 kg*m/s (to the East)
Pb = MbVb& = 5*20 = 100 kg m/s (to the North)

The modulus of the impulse after inelastic hitting is
radic; (Pa2 + Pb2) = raidc; (802 + 1002) = 128.1 kg m/s
The speed :
128.1 / (8 + 5) = 9.85 m/s
tan (angle to the North) = 80/100 = 0.8
38.66 degrees from North to East.

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Assignment Expert
15.07.11, 17:55

You are welcome!

Chalani Jayawardena
15.07.11, 14:30

Thank you so much for helping me...And I'm really sorry for my bad English..