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# Answer to Question #36131 in Mechanics | Relativity for ammy

Question #36131
a man moves in an open field such that after moving 10m on a straight line , he makes a sharp turn of 60 degree to his left . the total displacement after 8 such turn is equal to ??????????????
1
Expert's answer
2013-10-16T08:14:19-0400
If man only makes 8 turns (he does not move on the straight line) then he consequently makes a sharp turn of 180 degrees to his left.

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#### Comments

sagarika
28.10.14, 12:04

since he takes a sharp turn of 60 degrees to left he makes an an angle of 120 degress to the inside,and 60 degrees to the outside.thus it will form a polygon with mease of interior angle 120 and exterior angle 60.thus it is a hexagon.thus 6 side after 6th turn it will complete 2 more turn spanning 2 more side of the hexagon.thus distance covered will be 20.but displace ment is asked,so we form a trianglr with 2 sides measuring 10 m and the angle between them is 120.thus by sin rule of triangle: root3 * side

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