# Answer to Question #35376 in Mechanics | Relativity for courtneyhh

Question #35376

A criminal is escaping across a rooftop and runs off the roof horizontally at a speed of 5.2 m/s, hoping to land on the roof of an adjacent building. Air resistance is negligible. The horizontal distance between the two buildings is D, and the roof of the adjacent building is 2.0 m below the jumping-off point. Find the maximum value for D.

Expert's answer

what time is needed to pass 2 m verticaly?

s=gt^2/2, t = sqrt(2s/g)=0.64s

in 0.64 seconds he can pass horizontally

D=t*v = 0.64*5.2 = 3.32m

So the maximum for D is 3.32 m

s=gt^2/2, t = sqrt(2s/g)=0.64s

in 0.64 seconds he can pass horizontally

D=t*v = 0.64*5.2 = 3.32m

So the maximum for D is 3.32 m

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