# Answer to Question #35156 in Mechanics | Relativity for Kristen Woods

Question #35156

Use the 5-step method and be sure to include units where appropriate. Round your answers to the correct number of significant digits.

Adjust the density formula and solve the problems below:

Pure gold has a density of 119.32 g/cm3. How large would a piece of gold be if it had a mass of 3118.97 g?

Adjust the density formula and solve the problems below:

Pure gold has a density of 119.32 g/cm3. How large would a piece of gold be if it had a mass of 3118.97 g?

Expert's answer

The density formula is

ρ(g/cm^3) = (m(g))/(Vcm^3))

According to this formula the volume of the metal is

V(cm^3) = □((m(g))/(ρ(g/cm^3))

V(cm^3) = 3118.97/119.32 = 26.1 cm^3

Answer: V = 26.140 cm^3

ρ(g/cm^3) = (m(g))/(Vcm^3))

According to this formula the volume of the metal is

V(cm^3) = □((m(g))/(ρ(g/cm^3))

V(cm^3) = 3118.97/119.32 = 26.1 cm^3

Answer: V = 26.140 cm^3

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