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Answer to Question #34802 in Mechanics | Relativity for Aman
Question #34802
While finding propagation of errors in power function
z=(A^x)(B^y)
taking log
log Z = x log A + y log B
On differentating both sides
dZ/Z = x dA/A +y dB/B
Doubt : How above equation is true although Z is function of A&B not vice-versa
Kindly explain how this derivative has been taken
z=(A^x)(B^y)
taking log
log Z = x log A + y log B
On differentating both sides
dZ/Z = x dA/A +y dB/B
Doubt : How above equation is true although Z is function of A&B not vice-versa
Kindly explain how this derivative has been taken
Expert's answer
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