A car starts from rest and accelerates uniformly for 10 s to a velocity of 8 m/s . It runs at a constant velocity and is finally brought at rest in 64 m with a constant retardation . the total distance covered by the car is 584 m . find the value of acceleration, retardation and total time taken.
1. Using the equations of the accelerated motion we have:
v = a*t, s = (a*t2)/2 t = 10s v = 8m/s a = v/t = 0.8 m/s2 s = 40 m
2. retardation moving
s = 64 m v = 8 m/s using formula: r = v2/(2*s) => retardation r = 0.5 m/s2 v = t*r => t = v/r =16 s
3. A car runs with uniform velocity v = 8 m/s a=0 s = 584 - 40 - 64 = 480m t = s/v = 60 s